@shailendrah

धृति: क्षमा दमोऽस्तेयं शौचमिन्द्रिय निग्रह: । धीर्विद्या सत्यमक्रोधो दशकं धर्म लक्षणम् ।।

 USA
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Joined February 2009
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Replying to @shailendrah @ponnappa_pran @ShefVaidya
Here is a description of 16 gunas of Shri Rama. People need to do padavichchedam: शान्तं शाश्वतमप्रमेयमनघं निर्वाणशान्तिप्रदं ब्रह्माशंभुफणीन्द्रसेव्यमनिशं वेदांतवेद्यं विभुम्‌।। रामाख्यं जगदीश्वरं सुरगुरुं मायामनुष्यं हरिं वन्देऽहं करुणाकरं रघुवरं भूपालचूडामणिम्‌।।
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तेशे बग़ैर मर न सका कोहकन 'असद' सरगश्ता-ए-ख़ुमार-ए-रुसूम-ओ-क़ुयूद था
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Simplify: (sqrt(12)/(sqrt(15)+sqrt(3)))^12
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2*sqrt(3)/(sqrt(3)(sqrt(5)+1))=(sqrt(5)-1)/3
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8^x+2^x=130 find x.
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y=2^x=>y(y^2+1)=130=>by inspection y=5 by inspection. x=ln5/ln2
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3^x=x^9 find the value of x.
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xln3=9lnx=>lnx/x=ln3/9=k=>x=e^kx=>-kxe^-kx=-k Now apply lambda function. x=-W(-k)/k =>9W(-ln3/9)/ln3
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Find the value of X: X^1/10+X^1/15+X^1/30=155
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Here is the solution: y=X^1/30 => y(y^2+y+1)=5*31=> y=5 is a root by inspection = x^1/30=5 => x=5^30; There are other solutions in the domain of complex numbers.
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3^x+sqrt(3)^(x+4)+20=0 Solve for x.
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Solve this: a^2-b=31; b^2-a=31
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George Allen's quotes: Coaching philosophy: "The man who can accept defeat and take his salary without feeling guilty is a thief." On Success and Defeat: "In sports, the only measure of success is a victory. We must sacrifice everything to this end."
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On Winning & Losing: "Every time you win, you're reborn; when you lose, you die a little." On Urgency: "The future is now" (on his preference for trading picks for proven veterans). On Preparation: "What you do in the off-season determines what you do in the regular season."
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Definition: Jauhar was a historic rite of collective self-immolation performed by women, children, and other dependents of a besieged fort or town.
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Purpose: It was carried out when defeat by an invading army was certain, driven by the desire to avoid capture, enslavement, and dishonor.
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Follow-up (Shaka): Self-immolation was typically followed by surviving male warriors charging into battle to die honorably, an act known as shaka.
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Which is greater? 222^333 or 333^222.
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A=222^333 B=333^222=>A/B=(222^111*3)/(333^111*2)=> ((222^3)/(333^2))^111=> (888/9)^111 Hence 222^333 is much greater than 333^222.
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Solve f(1/x) = sqrt(x^2+1). What is f(x)?
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y=1/x=>x=1/y; f(y)=sqrt((1/y^2)+1)=>f(x)=sqrt((1/x^2)+1)
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Solve: (x+3)(x+5)(x+7)(x+9)=21
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mean(3, 5, 7, 9)=6 y=x+6 (x-3)(x-1)(x+1)(x+3)=(x^2-9)(x^2-1)=21 y^2-10y+9=21 y=7, 3 y=+/-sqrt(7), +/-sqrt(3) x=sqrt(7)-6, -sqrt(7)-7, sqrt(3)-6 -sqrt(3)-6
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